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Find the pH of a buffer solution containing 0.20 mole per litre sodium acetate and 0.18 mole per litre acetic acid, K_a for acetic acid is 1.8 times 10^-5. |
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Answer» Solution :`ph=Pk_a+LOG([salt])/([acid])` GIVEN that `K_a=1.8 TIMES 10^-5` `THEREFORE pK_a=-log(1.8 times 10^-5)` `=5-log 1.8` `=5-0.26=4.74` `therefore pH=4.74+log (0.20)/(0.18)` `=4.74+log 10/9` `=4.74 +log 10/9` `4.74+1-0.95` `=5.74-0.95` `=4.79` |
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