1.

Find the point on the curve Y=x^2-2x+3 where the tangent is parallel to y-axis​

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Answer:

Step-by-step explanation:

The tangent cannot be parallel to the y-axis.

since this is a parabola.

So, tangent can only be parallel to the x-axis.

For tht point, u have to find the MINIMA => dy/dx = 0

so dy/dx = 2x-2

so x=1

then when x=1, y = 1^2 - 2*1 +3 = 2

so the REQUIRED point is (1,2)


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