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| 1. |
Find the point on X-axis which is equidistantfrom A(-3, 4) and B(1,4). |
| Answer» PLS make my answer brilliantStep-by-step explanation:Let the POINT on the x-axis be P(a, 0).PA=(a−(−3))2+(0−4)2=(a+3)2+16PB=(a−1)2+(0−(−4))2=(a−1)2+16PA2=PB2⇒(a+3)2+16=(a−1)2+16⇒a2+6a+9=a2−2a+1⇒8a=−8⇒a=−1(a,0)=(−1,0) | |