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Find the point on Y-axis which is equidistant from the points `(-5,2)and (9,-2).` |
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Answer» Let the given points be A(-5, 2) and B(9, -2) and let the required point be P(0, y).Then, `PA = PB rArr PA^(2) = PB^(2)` `rArr (0+5)^(2) + (y-2)^(2) = (0-9)^(2) + (y+2)^(2)` `rArr 5^(2) + (y-2)^(2) = (-9)^(2) + (y +2)^(2)` `rArr 25 + (y-2)^(2) = 81 +(y +2)^(2)` `rArr (y+2)^(2) -(y-2)^(2) = 25-81` `rArr ` 8y =-56 `rArr` y = -7 Hence, the required point is P(0, -7). |
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