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Find the point to which the origin should be shifted so that theequation `y^2-6y-4x+13=0`is transformed to the form `y^2+A x=0.` |
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Answer» `y^2+Ax=0` `y^2-6y+(3^2-3^2)-4x+13=0` `(y-3)^2+4-4x=0` `(y-3)^2+4(1-x)=0` `(y-3)^2-4(x-1)=0` `y^2+Ax=0` `A=-4`.`y-3=0` `y=3` `x-1=0` `x=1` Point(1,3). |
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