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Find the point where the line `x+y=6`is a normal to the parabola `y^2=8xdot`A. (18, -12)B. (4, 2)C. (2, 4)D. (3, 3) |
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Answer» Correct Answer - C We have, Slope of the normal= (Solpe of the line x + y = 6) = -1 The coordinates of the foot of the normal are `(am^(2), -2am)`. Here a = 2 and m = -1. So, the required point is (2, 4). |
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