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Find the points of contact `Q`and `R`of a tangent from the point `P(2,3)`on the parabola `y^2=4xdot` |
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Answer» Let points Q and R be `(t_(1)^(2),2t_(1))and(t_(2)^(2).2t_(2))`. Point of intersection of tangent at Q and R is `(t_(1)t_(2),(t_(1)+t_(2)))-=(2,3)`. `:." "t_(1)t_(2)=2andt_(1)+t_(2)=3`. Solving, we get, `t_(1)=1andt_(2)=2`. So, Q is (1,2) and R is (4,4). |
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