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Find the points on the ellipse `(x^2)/4+(y^2)/9=1`on whichthe normals are parallel to the line `2x-y=1.` |
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Answer» The normal at `P(2 cos theta,3 sin theta)` is `(2x)/(cos theta)-(3y)/(sin theta)=-5` Now, this normal is parallel to 2x-y1. Then, `(2//cos theta)/(3//sin theta)=2` or ` tan theta=(3)/(1)` `cos theta=+-and sin theta=+-(3)/(sqrt(10))` Hence, the points are `(2sqrt(10),9sqrt10),(-2//sqrt(10),-9//sqrt(10))` |
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