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Find the points on `y-a xi s`whose perpendicular distance from the line `4x-3y-12=0`is `3.` |
Answer» Correct Answer - (0,1) and (0,9) Let the required point be `P(0, alpha)`. It is given that the length of the perpendicular from `P(0, alpha)` on 4x-3y-12=0 is 3. Therefore, `|(4(0)-3alpha-12)/(sqrt(4^(2)+(-3)^(2)))|=3` `"or " |3alpha+12| = 15` `"or " |alpha+4| = 5` `"or " alpha+4 =+-5` `"or " alpha = 1, -9` Hence, the required points are (0,1) and (0,-9). |
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