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Find the position of the image formed by the lens combination given in the figure. |
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Answer» SOLUTION :Image FORMED by the fist lens `(1)/(v_(1)) -(1)/(u_(1)) = (1)/(f_(1))` `(1)/(v_(1)) - (1)/(-30) = (1)/(10) or v_(1) = 15 cm ` The image formed by the first lens serves as the object for the second. This is at a DISTANCE of (15 -5) cm = 10 cm to the right of the second lens. though the image is real, it serves as a virtual object for the second lens, Which means that the rays appear to come from it for the second lens. `(1)/(v_(2)) - (1)/(10) = (1)/(-10) or v_(2) = infty` The virtual image is formed at an infinite distance to the left of the second lens. This ACTS as an object for the THIRD lens. `(1)/(v_(3)) - (1)/(u_(3)) = (1)/(f_(3))"" or "" (1)/(v_(3)) = (1)/(infty) + (1)/(30) "or" v_(3) = 30` cm The final image is formed 30 cm to the right of the third lens. |
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