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Find the potential difference between and N in the given branch of a circuit figure. |
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Answer» Solution :Let us have a closed CIRCUIT by joining to N with dotted lines. Let the potentials at M and N be `V_(M)` and `V_(N)` respectively. Following counter clockwise direction and applying Kirchhoff.s SECOND LAW, we get `(V_(N)-V_(M))-4+(0.4xx1)+(0.4xx2)-6(0.4xx1)+(0.4xx6)=0` `(V_(N)-V_(M))-10+0.4+0.8+0.4+2.4=0` `V_(N)-V_(M)=6V` |
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