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Find the potential difference between point A and B in an electric field barE=(2hati+3hatj+4hatk)NC^(-1) where barr_(A)=(hati+2hatj+hatk)m and barr_(B)=(2hati+hatj-2hatk)m. |
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Answer» Solution :We know that `dV= -barE.dbarr` `V_(AB)=V_(A)-V_(B)= -int_(A)^(B) barE.dbarr` `= -int_("(2,1,-2)")^("(1,-2,1)") (2hati+3hatj+4hatk).(dxhati+dyhatj+dzhatk)` `=-int_("(2,1,-2)")^("(1,-2,1)") (2dx+3dy+4dz)` `= -(2x+3y+4z)|_("(2,1,-2)")^("(1,-2,1)")=-1` VOLT |
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