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Find the potential of V = 60sin θ/r^2 at P(3,60,25)(a) 5.774(b) 6.774(c) 7.774(d) 8.774I got this question during an interview for a job.This is a very interesting question from Electric Potential in division Electrostatic Fields of Electromagnetic Theory

Answer»

The CORRECT ANSWER is (a) 5.774

Explanation: V = 60sin θ/R^2, put r = 3m, θ = 60 and φ = 25, V = 60 sin 60/3^2 = 5.774 VOLTS.



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