InterviewSolution
Saved Bookmarks
| 1. |
Find the power of a person who can chew `30g` of ice in one minute. Latent heat of ice `=80cal//gm`, `J=4.2`joule`//`cal. |
|
Answer» Mass of ice chewe, `m=30g` time taken,`=1min=60s.` Latent heat of ice, `L=80cal//g` Heat produced `=mL=30xx80=2400cal`. `=2400xx4.2J.` Power `=("work")/("time")=(2400xx4.2)/(60)"watt"=168 "watt"` |
|