InterviewSolution
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Find the principal solutions of the following equation:sinθ = 1/2 |
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Answer» The general solution of sin θ = sin \(\propto\) is θ = nπ + (-1 )n \(\propto\), n ∈ Z Now, sinθ = \(\cfrac{1}{2}\) = sin \(\cfrac{\pi}{6}\).....[∵ sin\(\cfrac{\pi}{6}\) = \(\cfrac{1}{2}\)] ∴ the required general solution is θ = nπ + (-1)n \(\cfrac{\pi}{6}\), n ∈ Z. |
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