1.

Find the principal solutions of the following equation:sinθ = 1/2

Answer»

The general solution of sin θ = sin \(\propto\) is

θ = nπ + (-1 )n \(\propto\), n ∈ Z

Now, sinθ = \(\cfrac{1}{2}\) = sin \(\cfrac{\pi}{6}\).....[∵ sin\(\cfrac{\pi}{6}\) = \(\cfrac{1}{2}\)]

∴ the required general solution is

θ = nπ + (-1)n \(\cfrac{\pi}{6}\), n ∈ Z.



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