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Find the principalvalue of `sec^(-1)((-2)/(sqrt(3)))`A. `pi/6`B. `-pi/6`C. `(5pi)/6`D. `(7pi)/6`

Answer» Correct Answer - C
Let `sec^(-1)(-2/sqrt(3))=x`, where `x in [0,pi]-{pi/2}`
Then, `secx=-2/sqrt(3)=-secpi/6 = sec(pi-pi/6)=sec(5pi)/6 rArr x=(5pi)/6`.


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