1.

FIND THE PROBABILITY DISTRIBUTION OF THE NO. OF TAILS IN TWO TOSSES OF A COIN.​

Answer»

Answer ❤️

Let random variables X denotes the number of Tails, then X can TAKE the values 0,1 & 2 .

P = probability of getting an TAIL in a throw of coin = ½, W = 1 - P = ½

p(0) = QQ = ½×½×¼

p(1) = pq + qp = { ½×½} + { ½×½} = ¼+¼= ½

p(2) = pp = {½×½} = ¼

Thus, the probability distribution is:

X = P(X)

0 = ¼

1 = ½

2 = ¼

hope help you

brainlist please ❤️ uff..


Discussion

No Comment Found

Related InterviewSolutions