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Find the probability of 53 Sundays and 53 Mondays in a leap year.A. `(2)/(7)`B. `(4)/(7)`C. `(3)/(7)`D. `(1)/(7)` |
Answer» Correct Answer - C A leap year consists of 366 days comprising of 52 weeks and 2 days. There are 7 possibilities for these 2 extra days viz., (i) Sunday, Monday (ii) Monday, Tuesday (iii) Tuesday, Wednesday (iv) Wednesday, Thursday (v) Thursday, Friday (vi) Friday, Saturday (vii) Saturday, Sunday. Let us consider two events : A : The leap year contains 53 Sundays B : The leap year contains 53 Mondays. We have, `P(A)=(2)/(7),P(B)=(2)/(7), P(A cap B)=(1)/(7)` Required probability `=P(A cup B)` `= P(A)+P(B)-P(A cap B)=(2)/(7)+(2)/(7)-(1)/(7)=(3)/(7)` |
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