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Find the probability of a non-leap year having 53 Sundays. |
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Answer» 1 year = 365 days And a year has 52 weeks So 52 × 7= 364 days So now remaining 1 day can be any day i.e. Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday So P(probability of a non-leap year having 53 Sundays) = 1/7 |
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