1.

Find the probability of a non-leap year having 53 Sundays.

Answer»

1 year = 365 days

And a year has 52 weeks

So 52 × 7= 364 days

So now remaining 1 day can be any day i.e. Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday

So P(probability of a non-leap year having 53 Sundays) = 1/7



Discussion

No Comment Found

Related InterviewSolutions