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Find the probability of getting 53 Fridays in a leap year. (A) 3/7(B) 4/7(C) 2/7(D) 5/7 |
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Answer» The correct option is: (C) 2/7 Explanation: Leap year contains 366 days. => 52 weeks + 2 days 52 weeks contain 52 Fridays. We will get 53 Fridays if one of the remaining two days is a Friday. Total possibilities for two days are: (Sunday, Monday), (Monday, Tuesday), (Tuesday, Wednesday), (Wednesday, Thursday), (Thursday, Friday), (Friday, Saturday), (Saturday, Sunday) There are 7 possibilities and out of these 2 are favourable cases ∴ Required probability = 2/7 |
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