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Find the probability of getting vowels in the first, third and sixth place when all the letters of the word, ORANGE are arranged in nil possible ways. |
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Answer» Here, there are total 6 letters O, R, A, N, G, E in the word ORANGE. ∴ The total number of ways of arranging these six letters, n = 6P6 = 6! = 6 × 5 × 4 × 3 × 2 × 1 = 720 A = Event of getting vowels in the first, third and sixth place. ∴ The favourable outcomes for the event A are obtained as follows: ∴ m = 3P3 × 3P3 = 3! × 3! = 6 × 6 = 36 Hence, P(A) = \(\frac{m}{n} = \frac{36}{720} = \frac{1}{20}\) |
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