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Find the probability that a leap year will have 53Friday or 53 Saturdays. |
Answer» Correct Answer - `(3)/(7)` There are 366 days in a leap year. Also, there are 52 weeks and 2 days. The prossible combinations of two days are as follows: Sunday-Monday, Monday-Tuesday, Tuesday-Wednesday, Wednesday-Thursday, Thurday-Friday, Friday-Saturday, Saturday-Sunday Now, let E be the event in which leap year will have 53 Fridays or 53 Saturdays. We observe that there are three possibilities for event E, viz. Thursday-Friday, Friday-Saturday, and Saturday-Sunday. Since each pair of 2 equally likely, `P(E) = (1)/(7) + (1)/(7) + (1)/(7) = (3)/(7)` |
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