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Find the product and their values for a = -1 , b= 2, c= 1 (4a-2b+3c)(2a-3b) |
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Answer» Step-by-step explanation: 2a(4a-2b+3c)-3B(4a-2b+3c) 8asquare -4ab+6ac-12ab+6bsquare-9bc 8asquare-16ab+6ac+6bsquare-9bc by PUTTING value 8(-1)square-16(-1)(2)+6(-1)(1)+6(2)square-9(2)(1) (-8)-(-32)+(-6)+24-18 (-8)-(-32)+(-6)+6 -8-(-32) -8+32=24 |
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