1.

Find the product and their values for a = -1 , b= 2, c= 1 (4a-2b+3c)(2a-3b)

Answer»

Step-by-step explanation:

2a(4a-2b+3c)-3B(4a-2b+3c)

8asquare -4ab+6ac-12ab+6bsquare-9bc

8asquare-16ab+6ac+6bsquare-9bc

by PUTTING value

8(-1)square-16(-1)(2)+6(-1)(1)+6(2)square-9(2)(1)

(-8)-(-32)+(-6)+24-18

(-8)-(-32)+(-6)+6

-8-(-32)

-8+32=24



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