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Find the product of (2a–b + 3c)( 4a^2+b^2+ 9c^2+ 2ab + 3bc –6ca ) |
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Answer» 8a3−27b3−8c3−36abcStep-by-step EXPLANATION:[2A+(−3b)+(−2c)][(2a)2+(−3b)2+(−2c)2−2a×(−3b)−(−3b)(−2c)−(2a)(−2c)] (x+y+z)(x2+y2+z2−xy−yz−zx) (wherex=2a,y=−3b andz=−2c) =x3+y3+z3+3xyz=(2a)3+(−3b)3+(−2c)3−3×2a×(−3b)×(−2c) =8a3−27b3−8c3−36abc |
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