Find the product of (2a–b + 3c)( 4a^2+b^2+ 9c^2+ 2ab + 3bc –6ca )

1.	Find the product of (2a–b + 3c)( 4a^2+b^2+ 9c^2+ 2ab + 3bc –6ca )
Answer» <html><body><p>8a3−27b3−8c3−36abcStep-by-step <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a>:[<a href="https://interviewquestions.tuteehub.com/tag/2a-300249" style="font-weight:bold;" target="_blank" title="Click to know more about 2A">2A</a>+(−3b)+(−2c)][(2a)<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+(−3b)2+(−2c)2−2a×(−3b)−(−3b)(−2c)−(2a)(−2c)] (x+y+z)(x2+y2+z2−xy−yz−zx) (wherex=2a,y=−3b andz=−2c) =x3+y3+z3+3xyz=(2a)<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>+(−3b)3+(−2c)3−3×2a×(−3b)×(−2c) =8a3−27b3−8c3−36abc</p></body></html>

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