1.

Find the product of uncertainty in position and velocity for an electron of mass 9.10 xx 10^(-31) kg. (h= 6.62 xx 10^(-34) J.s, " i.e., " kg m^(2) s^(-1))

Answer»

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Solution :We have, `Delta x. Delta p= (H)/(4pi)`
`Delta x.(m xx Delta v) = (h)/(4pi)`
or `Deltax. Detla v= (h)/(4pi m)`
`=(6.62 xx 10^(-34) (kg.m^(2).s^(-1)))/(4 xx 3.14 xx 9.10 xx 10^(-31) (kg))`
`=5.8 xx 10^(-5) m^(2) s^(-1)`


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