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Find the proportion of work done in breaking a big spherical drop of water into n small spherical drops eac h of radius r |
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Answer» SOLUTION :`4/3 pi R^3 = N xx 4/3 pir^3` `therefore r = R/n^(1/3)` `therefore r^2 = R^2/(n^2/3)` WORK done = `[4pinR^2/n^(2/3) - 4piR^2] T` W = `4piR^2T[n^(1/3) - 1]` `therefore` W = `n^(1/3)` -1 |
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