1.

Find the Q-value and the kinetic energy of the emitted alpha - particle in the alpha - decay of ._(86)^(220)Rn. Given m (._(88)^(226)Ra)=226.02540 u, m (._(86)^(222)Rn)=222.01750 u, m (._(86)^(222)Rn)=220.01137 u, m (._(84)^(216)Po) = 216.00189 u.

Answer»

SOLUTION :PROCEEDING as above, in CASE of `._(86)RN^(220)`
Q = 6.41 MeV
K.E of a particle
`= ((A-4)Q)/(A) = ((220-4))/(220)xx6.41 = 6.29 MeV`


Discussion

No Comment Found

Related InterviewSolutions