Find the Q-value and the kinetic energy of the emitted o-particle in the a-decay of (a) " "_(88)^(226)Ra and (b) " "_(86)^(220)Rn. Given : m(" "_(88)^(226Ra)=226.02540 u, m(" "_(86)^(222)Rn)=222.01750 u, m(" "_(86)^(220)Rn)=220.01137u, m(" "_(84)^(216)Po)=216.00189 u.

Find the Q-value and the kinetic energy of the emitted o-particle in t

1.	Find the Q-value and the kinetic energy of the emitted o-particle in the a-decay of (a) " "_(88)^(226)Ra and (b) " "_(86)^(220)Rn. Given : m(" "_(88)^(226Ra)=226.02540 u, m(" "_(86)^(222)Rn)=222.01750 u, m(" "_(86)^(220)Rn)=220.01137u, m(" "_(84)^(216)Po)=216.00189 u.
Answer» SOLUTION :(a) `ALPHA`-DECAY of `" "_(88)^(226)Ra` is having the reaction equation : `" "_(88)^(226)Ra (to)" "_(86)^(222)Rn+" "_(2)^(4)He+Q` `therefore Q_(value)=(M_(Ra) - M_(Rn) - M_(He))c^(2) = (226.02540-222.01750-4.002603)uxx931.5(MeV)/u=4.93MeV` `therefore` Kinetic energy of emitted `alpha`-particle, K=`((A-4)/A)Q=222/226xx4.93MeV=4.85MeV` (B)`alpha`-decay equation of `" "_(86)^(220)Rn` is: `" "_(86)^(220)Rn (to) " "_(84)^(216)Po +" "_(2)^(4)He +Q` `therefore Q_(value)=(M_(Rn)-M_(Po)-M_(He)).c^(2)=(220.01137-216.00189-4.002603)uxx931.5(MeV)/u=6.41MeV` `therefore` Kinetic of emitted `alpha`-particle K=`((A-4)/A).Q=216/220xx6.41MeV=6.29MeV`.

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Find the Q-value and the kinetic energy of the emitted o-particle in the a-decay of (a) " "_(88)^(226)Ra and (b) " "_(86)^(220)Rn. Given : m(" "_(88)^(226Ra)=226.02540 u, m(" "_(86)^(222)Rn)=222.01750 u, m(" "_(86)^(220)Rn)=220.01137u, m(" "_(84)^(216)Po)=216.00189 u.

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