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Find the Q-value of the emitted alpha-particle in the alpha-decay of ._(88)^(226)Ra.m_(alpha)=4.00260u m(._(88)^(226)RA)=226.02540u m(._(86)^(222)Rn)=222.01750u |
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Answer» 8.93 MeV `Deltam=.0053am U` `Q=Deltamxx931.25` `Q=4.93MeV` |
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