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Find the quadratic polynomial , the sum and product of zeroes is ax-3 and 2,respectively |
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Answer» Answer: (1-a)x²+3x+2 Step-by-step explanation: Given that, sum of the zeroes of the polynomial is = ax-3 product of the zeroes of the polynomial is = 2 LET the zeroes of the polynomial be α & β as we KNOW that, α+β = -b/a ⇒ax-3 = -b/a→(1) (∵Given) α.β = c/a ⇒2 = c/a→(2) (∵given) the general form of quadratic EQUATION is K(x²-(α+β)x+α.β) (∵Where k is any constant) ⇒k(x²-(ax-3)x+2) ⇒k(x²-(ax²-3x)+2) ⇒k(x²-ax²+3x+2) ⇒k((1-a)x²+3x+2) let, k=1 ⇒1((1-a)x²+3x+2) ⇒(1-a)x²+3x+2 ∴the quadratic polynomial is (1-a)x²+3x+2. HOPE THIS WOULD BE HELPFUL FOR YOU |
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