1.

Find the r.m.s value of load current based on data given in the question no 10.

Answer»

`100xx10^(-3)A`
`50xx10^(-3)A`
`200xx10^(-3)A`
`150xx10^(-3)A`

SOLUTION :`V_(0)=sqrt(2)V_(r.m.s)=sqrt2xx50=70.7`
Max. load current, `I_(0)=(V_(0))/(r+R)`
Mean load current, `I_(m)=(2I_(0))/(PI)`
`I_(r.m.s)=(I_(0))/(SQRT2)`


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