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Find the radius of curvature of the convex surface of a plano-convex lens, whose focal length is 0.3 m and the refractive index of the material of the lens is 1.5. |
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Answer» Solution :Here FOCAL length of a plano-convex lens f= +0.3 m and refractive index of lens n = 1.5 For a plano-convex lens let `R_(1) = +R`and `R_2 = - infty`. Applying lens maker.s formula: `1/f = (n-1)(1/R_(1) - 1/R_(2))`, we get `1/0.3 = (1.5-1) (1/R -1/(-infty)) = 0.5/R` `rArr R = 0.3 XX 0.5 = 0.15 m` or 15 CM |
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