

InterviewSolution
Saved Bookmarks
1. |
Find the range of `(alpha,2+alpha)`and `((3alpha)/2,a^2)`lie on the opposite sides of the line `2x+3y=6.` |
Answer» Correct Answer - `alpha in (-oo, -2) uu (0,1)` We have L(x,y) = 2x+3y-6 ` therefore L(alpha, 2+alpha) = 5alpha` `" and " L((3)/(2) alpha, alpha^(2)) = 3alpha + 3alpha^(2)-6` Given points lie on the opposite sides of the line if `5alpha (3alpha + 3alpha^(2)-6) lt 0` `rArr alpha (alpha + 2)(alpha-1) lt 0` `rArr alpha in (-oo, -2) uu (0,1)` |
|