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find the ratio in which the line segment joining the points (-3,10) and (6,-8) is divided by (-1,6). |
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Answer» (-3,10) &(6,-8) is DIVIDED by PT (-1,6)lets take m:n as the ratio in which the LINE is divided by (-1,6)using point formula(-1,6) =[mx2+nx1/m+n , my2+ny1/m+n](-1,6) =[-6m-3n/m+n , -8m+10n/m+n]-1= -6m-3n/m+n-(m+n)= -(6m+3n)m+n= 6m+3nn-3n=6m-m2n=5m-l2/5=m/n•°• the ratio is 2:5leave a like if u get it..plss mark the answer as brainlest |
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