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Find the ratio of de-Broglie wavelengths associated with two electrons accelerated through 25 and 36 V. |
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Answer» SOLUTION :`V_(1) = 25 V, V_(2) = 36 V` De-Broglie wavelength of an ELECTRON: `LAMBDA=(1.227)/(sqrtV)` `lambda_(1)=(12.27)/(sqrtV_(1))` and `lambda_(2)= (12.27)/(sqrtV_(2))` `:. (lambda_(1))/(lambda_(2))=sqrt((V_(2))/(V_(1)))=sqrt((36)/(25))` `(lambda_(1))/(lambda_(2))=(6)/(5)` |
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