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Find the ratio of de-Broglie wavelengths associated with two electrons accelerated through 25V and 36V. |
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Answer» Solution :As de-Broglie wavelength of electron `LAMDA=(h)/(sqrt(2emV))`, HENCE, `(lamda_(1))/(lamda_(2))=sqrt((V_(2))/(V_(1)))=sqrt((36)/(25))=(6)/(5)`. |
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