Saved Bookmarks
| 1. |
Find the ratio of energies of photons produced due to transition of an electron of hydrogen atom from its . (i)second permitted energy level to the first level, and (ii) the highest permitted energy level to the first permitted level. |
|
Answer» Solution : Energy of an electron in nth permitted energy LEVEL is GIVEN by `E_(n th) = (13.6)/(n^(2)) eV` Energy of photon produced due to transition of an electron from second permitted energy level to the firstlevel ` E = E_(2) =- (13.6)/((2)^(2)) = (-(13.6)/((1)^(2)))eV = 10.4 eV` and energy of photon produced due to transition of an electron from highest permitted energy level to the FIRST level TOTHE firstlevel ` E = E - E_(1) = (13.6)/((oo)^(2)) - (-(13.6)/(1))eV = 13.6eV` `RARR "" (E)/(E) = (10.4)/(13.6) = (3)/(4)` |
|