Find the ratio of refractive index of medium 2 to that of medium 1, when the Brewster angle is 60 degree.(a) 0.707(b) 1.5(c) 0.866(d) 1.732I have been asked this question in semester exam.This is a very interesting question from Brewster Angle in section EM Wave Propagation of Electromagnetic Theory

Find the ratio of refractive index of medium 2 to that of medium 1, wh

1.	Find the ratio of refractive index of medium 2 to that of medium 1, when the Brewster angle is 60 degree.(a) 0.707(b) 1.5(c) 0.866(d) 1.732I have been asked this question in semester exam.This is a very interesting question from Brewster Angle in section EM Wave Propagation of Electromagnetic Theory
Answer» Right option is (d) 1.732 For explanation I would say: The tangent of the Brewster angle is the ratio of the MEDIUM 2 permittivity to the medium 1 permittivity. Thus tan θb = (n2/n1). Given that θb = 60 DEGREE, the ratio n2/n1 will be tan 60 = 1.732.

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