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Find the real values of x and y for which`(1+i)y^2+(6+i)=(2+i)x ` |
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Answer» `(1+i)y^2+(6+i) = (2+i)x` `=>y^2+iy^2 + 6+i = 2x+ix` `=>(y^2+6)+i(y^2+1) = 2x + ix` Comparing real and imaginary parts, `:. y^2+6 = 2x->(1)` `y^2+1 = x` `=>y^2 = x -1 ->(2)` Putting value of `y^2` in (1), `=> x-1+6 = 2x => x = 5` `:. y^2 = 5-1 = 4` `=> y = +-2` `:. x = 5, y = +-2.` |
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