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Find The Remainder When 3^27 Is Divided By 5? |
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Answer» 3^27= ((3^4)^6) * (3^3) = (81^6) * 27 then unit DIGIT of (81^6) is 1 so on MULTIPLYING with 27, unit digit in the result will be 7. now, 7 when divided by 5 gives 2 as REMAINDER. 3^27= ((3^4)^6) * (3^3) = (81^6) * 27 then unit digit of (81^6) is 1 so on multiplying with 27, unit digit in the result will be 7. now, 7 when divided by 5 gives 2 as remainder. |
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