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find the remainder when p(x) =x^3-6x^2+2x-4 is divided by (1-2x), by using remainder theorem and verify the result by actual division |
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Answer» Step-by-step explanation: p(x) = x^3-6x^2+2x-4 1-2x=0 2x=1 x=1/2 p(1/2)=(1/2)^3-6(1/2)^2+2(1/2)-4 p(1/2)=(1/8)-6(1/4)+(2/2)-4 p(1/2)=(1/8)-(6/4)+1-4 p(1/2)=1/8-3/2-3 p(1/2) =8-12-3/8 p(1/2) =-15 I'm not sure bcoz same chapter is GOING on for me..hope this helps you |
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