1.

Find the remainder, when x^4+4x^3-5x^2-6x+7 is divided by x-3Sol=let f(x)=x^4+4x^3-5x^2-6x+7 and zero of x-3 is 3By the remainder theorm,f(x)=f(3)f(3)=(3)^4+4(3)^3-5(3)^2-6(3)+7=81+108-45-18+7=133There fore ,133 is remainder

Answer»

ANSWER:

ALREADY GIVEN answer. why



Discussion

No Comment Found

Related InterviewSolutions