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Find the remainder when x3-6x2+2x-4 is divided by 1-2x by remainder theorem |
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Answer» The ZERO of g(x)=1−2x is x= 2/1Now, by remainder theorem the remainder should be f(1/2) THEREFORE, f(1/2) = (1/2)3 -6(1/2)2 +2(1/2) -4 =(1/8)- 6(1/4)+1-4 =(1/8)- (6/4)-3 = 1-12-24/8 = -35/8 |
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