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Find the resultant of the vectors shown in fig by the component method |
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Answer» Solution :`vecR_(X) =lhati - 5COS 37^(@)hati -6cos 53hati` `vecR_(x) =1hati - 4hati -3.6hati, therefore vecR_(x), therefore vecR_(x) =-6.6hati` `vecR_(y) =3hatj + 5sin 37hatj - 6sin 53^(@)HATJ` `vecR_(y) = 3hatj + 3hatj - 4.8 hatj, therefore vecR_(y) = 1.2 hatj` `R=sqrt(R_(x)^(2) + R_(y)^(2)) =sqrt((-6.6)^(2) +(1.2)^(2)) = 6.7` |
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