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Find the rms value of current from t=0 to t=`(2pi)/(omega)` if the current avries as `i=I_(m)sin omegat`. |
Answer» `i_(rms) =sqrt((underset((pi)/(2omega))overset((2pi)/(omega))int I_(m)^(2) sin omegatdt)/((2pi)/(omega)))= sqrt((i_(m)^(2))/(2))=(I_(m))/(sqrt2)` | |