1.

Find the roots of quadratic equation 4√2x^2-7x-√2​

Answer»

Step-by-step explanation:4√2x²-7x-√2= 4√2x²-8x+X - √2 =4√2x(x-√2) +1 (x - √2) =(x - √2) (4√2x+1) HENCE root will be (x - √2)=0, (4√2x+1)=0X=√2 , x= -1/4√2 HOPE it's help you...Have a great DAY and thanks for asking dear ❤️❤️❤️



Discussion

No Comment Found

Related InterviewSolutions