1.

Find the rootsof equationx²-3x-m [m +3] =0where mis a constant​

Answer»

Answer:

you can use

Step-by-step EXPLANATION:

x = (-b±√(b²-4ac))/2a

a = 1

here b = -3;

c = -m[m+3]

so it will GO as

(3±√(9+4m(m+3)))/2


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