Find the Rydberg correction for the 3P term of a Na atom whose first exitation potential is 2.10V and whose valance electron in the normal 3S state has the binding energy 5.14 eV.

Find the Rydberg correction for the 3P term of a Na atom whose first e

1.	Find the Rydberg correction for the 3P term of a Na atom whose first exitation potential is 2.10V and whose valance electron in the normal 3S state has the binding energy 5.14 eV.
Answer» Solution :The ENRGY of the `3p` state must be `-(E_(0)-E varphi)` where `-E_(0)` is the ENERGY of the `3S` state. Then `E_(0)-evarphi_(1)=( ħR)/((3+alpha_(1))^(2))` so `alpha_(1)=sqrt(( ħR)/(E_(0)-e varphi_(1)))-3 =-0.885`

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Find the Rydberg correction for the 3P term of a Na atom whose first exitation potential is 2.10V and whose valance electron in the normal 3S state has the binding energy 5.14 eV.

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