Find the Rydberg correction for the `3P` term of a `Na` atom whose first exitation potential is `2.10V` and whose valance electron in the normal `3S` state has the binding energy `5.14 eV`.

Find the Rydberg correction for the `3P` term of a `Na` atom whose fir

1.	Find the Rydberg correction for the `3P` term of a `Na` atom whose first exitation potential is `2.10V` and whose valance electron in the normal `3S` state has the binding energy `5.14 eV`.
Answer» The enrgy of the `3p` state must be `-(E_(0)-e varphi)` where `-E_(0)` is the energy of the `3S` state. Then `E_(0)-evarphi_(1)=( ħR)/((3+alpha_(1))^(2))` so `alpha_(1)=sqrt(( ħR)/(E_(0)-e varphi_(1)))-3 =-0.885`

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Find the Rydberg correction for the `3P` term of a `Na` atom whose first exitation potential is `2.10V` and whose valance electron in the normal `3S` state has the binding energy `5.14 eV`.

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