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Find the set of those value(s) of `alpha` for which `(7-(5alpha)/4,alpha)` lies inside the ellipse `x^2/25+y^2/16=1` |
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Answer» Correct Answer - B `(7-(5)/(4)alpha, alpha)` lies inside the ellipse `(x^(2))/(25) + (y^(2))/(16) =1` `rArr ((7-(5)/(4)alpha)^(2))/(25)+(alpha^(2))/(16)-1 lt 0` `rArr ((28-5 alpha)^(2))/(400) + (alpha^(2))/(16) -1 lt 0` `rArr (28 - 5 alpha)^(2) + 25 alpha^(2) - 400 lt 0` `rArr 50 alpha^(2) - 140 alpha - 192 lt 0` `rArr (5 alpha -12) (5 alpha -16) lt 0` `rArr (12)/(5) lt alpha lt (16)/(5)` |
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